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Java-based LeetCode algorithm problem solutions, regularly updated
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package g0501_0600.s0541_reverse_string_ii;
// #Easy #String #Two_Pointers #2022_08_02_Time_1_ms_(100.00%)_Space_45_MB_(13.41%)
public class Solution {
public String reverseStr(String s, int k) {
StringBuilder res = new StringBuilder();
int p1 = 0;
int p2 = 2 * k - 1;
if (s.length() < k) {
res.append(reverse(s));
return res.toString();
}
while (p1 < s.length()) {
if (s.length() < p1 + k) {
res.append(reverse(s.substring(p1)));
} else {
res.append(reverse(s.substring(p1, p1 + k)));
if (s.length() < p2 + 1) {
res.append(s.substring(p1 + k));
} else {
res.append(s, p1 + k, p2 + 1);
}
}
p1 = p1 + 2 * k;
p2 = p2 + 2 * k;
}
return res.toString();
}
private String reverse(String s) {
StringBuilder sb = new StringBuilder();
sb.append(s);
sb.reverse();
return sb.toString();
}
}
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