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Java-based LeetCode algorithm problem solutions, regularly updated
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package g0601_0700.s0684_redundant_connection;
// #Medium #Depth_First_Search #Breadth_First_Search #Graph #Union_Find
// #2022_03_22_Time_0_ms_(100.00%)_Space_42.7_MB_(76.10%)
public class Solution {
private int[] par;
public int[] findRedundantConnection(int[][] edges) {
int[] ans = new int[2];
int n = edges.length;
par = new int[n + 1];
for (int i = 0; i < n; i++) {
par[i] = i;
}
for (int[] edge : edges) {
int lx = find(edge[0]);
int ly = find(edge[1]);
if (lx != ly) {
par[lx] = ly;
} else {
ans[0] = edge[0];
ans[1] = edge[1];
}
}
return ans;
}
private int find(int x) {
if (par[x] == x) {
return x;
}
return find(par[x]);
}
}
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