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Java-based LeetCode algorithm problem solutions, regularly updated
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package g0601_0700.s0699_falling_squares;
// #Hard #Array #Ordered_Set #Segment_Tree #2022_03_22_Time_8_ms_(91.03%)_Space_42.8_MB_(90.38%)
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
import java.util.Set;
import java.util.TreeSet;
public class Solution {
public List fallingSquares(int[][] positions) {
// Coordinate compression using TreeSet
Set unique = new TreeSet<>();
for (int[] square : positions) {
unique.add(square[0]);
unique.add(square[0] + square[1] - 1);
}
// converted the TreeSet to a List
List sorted = new ArrayList<>(unique);
// Storing the max heights for compressed coordinates
int[] heights = new int[sorted.size()];
// Our answer list
List list = new ArrayList<>(positions.length);
// Global Max
int max = 0;
for (int[] square : positions) {
// coordinate compression lookup
int x1 = Collections.binarySearch(sorted, square[0]);
int x2 = Collections.binarySearch(sorted, square[0] + square[1] - 1);
// get the current max for the interval between x1 and x2
int current = 0;
for (int i = x1; i <= x2; i++) {
current = Math.max(current, heights[i]);
}
// add the new square on the top
current += square[1];
// update the interval with the new value
for (int i = x1; i <= x2; i++) {
heights[i] = current;
}
// recalculate the global max
max = Math.max(max, current);
list.add(max);
}
return list;
}
}
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