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Java-based LeetCode algorithm problem solutions, regularly updated
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package g0701_0800.s0743_network_delay_time;
// #Medium #Depth_First_Search #Breadth_First_Search #Heap_Priority_Queue #Graph #Shortest_Path
// #2022_03_25_Time_3_ms_(99.87%)_Space_61.2_MB_(75.30%)
import java.util.Arrays;
import java.util.LinkedList;
import java.util.Queue;
public class Solution {
public int networkDelayTime(int[][] times, int n, int k) {
int[][] graph = new int[n + 1][n + 1];
for (int[] g : graph) {
Arrays.fill(g, -1);
}
for (int[] t : times) {
graph[t[0]][t[1]] = t[2];
}
boolean[] visited = new boolean[n + 1];
int[] dist = new int[n + 1];
Arrays.fill(dist, Integer.MAX_VALUE);
dist[k] = 0;
Queue spfa = new LinkedList<>();
spfa.add(k);
visited[k] = true;
while (!spfa.isEmpty()) {
int curr = spfa.poll();
visited[curr] = false;
for (int i = 1; i <= n; i++) {
if (graph[curr][i] != -1 && dist[i] > dist[curr] + graph[curr][i]) {
dist[i] = dist[curr] + graph[curr][i];
if (!visited[i]) {
spfa.add(i);
visited[i] = true;
}
}
}
}
int result = 0;
for (int i = 1; i <= n; i++) {
result = Math.max(dist[i], result);
}
return result == Integer.MAX_VALUE ? -1 : result;
}
}
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