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package g0801_0900.s0813_largest_sum_of_averages;
// #Medium #Array #Dynamic_Programming #2022_03_23_Time_4_ms_(97.01%)_Space_42.5_MB_(18.51%)
public class Solution {
public double largestSumOfAverages(int[] nums, int k) {
return helper(nums, k, 0, new Double[k + 1][nums.length]);
}
private double helper(int[] nums, int k, int idx, Double[][] memo) {
if (memo[k][idx] != null) {
return memo[k][idx];
}
double maxAvg = 0;
double sum = 0;
for (int i = idx; i <= nums.length - k; i++) {
sum += nums[i];
if (k - 1 > 0) {
maxAvg = Math.max(maxAvg, (sum / (i - idx + 1)) + helper(nums, k - 1, i + 1, memo));
} else if (i == nums.length - 1) {
maxAvg = Math.max(maxAvg, sum / (i - idx + 1));
}
}
memo[k][idx] = maxAvg;
return maxAvg;
}
}
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