• Home
• com.github.javadev
• leetcode-in-java
• 1.38
• source code
• readme.md

×

Project download

Many resources are needed to download a project. Please understand that we have to compensate our server costs. Thank you in advance.
Project price only 1 $

You can buy this project and download/modify it how often you want.

g0901_1000.s0957_prison_cells_after_n_days.readme.md Maven / Gradle / Ivy

957\. Prison Cells After N Days

Medium

There are `8` prison cells in a row and each cell is either occupied or vacant.

Each day, whether the cell is occupied or vacant changes according to the following rules:

*   If a cell has two adjacent neighbors that are both occupied or both vacant, then the cell becomes occupied.
*   Otherwise, it becomes vacant.

**Note** that because the prison is a row, the first and the last cells in the row can't have two adjacent neighbors.

You are given an integer array `cells` where `cells[i] == 1` if the ith cell is occupied and `cells[i] == 0` if the ith cell is vacant, and you are given an integer `n`.

Return the state of the prison after `n` days (i.e., `n` such changes described above).

**Example 1:**

**Input:** cells = [0,1,0,1,1,0,0,1], n = 7

**Output:** [0,0,1,1,0,0,0,0]

**Explanation:** The following table summarizes the state of the prison on each day:

Day 0: [0, 1, 0, 1, 1, 0, 0, 1]

Day 1: [0, 1, 1, 0, 0, 0, 0, 0]

Day 2: [0, 0, 0, 0, 1, 1, 1, 0]

Day 3: [0, 1, 1, 0, 0, 1, 0, 0]

Day 4: [0, 0, 0, 0, 0, 1, 0, 0]

Day 5: [0, 1, 1, 1, 0, 1, 0, 0]

Day 6: [0, 0, 1, 0, 1, 1, 0, 0]

Day 7: [0, 0, 1, 1, 0, 0, 0, 0]

**Example 2:**

**Input:** cells = [1,0,0,1,0,0,1,0], n = 1000000000

**Output:** [0,0,1,1,1,1,1,0]

**Constraints:**

*   `cells.length == 8`
*   `cells[i]` is either `0` or `1`.
*   1 <= n <= 109