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Java-based LeetCode algorithm problem solutions, regularly updated
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package g0901_1000.s0975_odd_even_jump;
// #Hard #Array #Dynamic_Programming #Stack #Ordered_Set #Monotonic_Stack
// #2022_03_31_Time_49_ms_(98.38%)_Space_69.1_MB_(5.18%)
import java.util.Arrays;
public class Solution {
private int[] valToPos;
public int oddEvenJumps(int[] arr) {
int size = arr.length;
boolean[] odd = new boolean[size];
boolean[] even = new boolean[size];
valToPos = new int[100001];
Arrays.fill(valToPos, -1);
valToPos[arr[size - 1]] = size - 1;
odd[size - 1] = even[size - 1] = true;
int count = 1;
for (int i = size - 2; i >= 0; i--) {
int curVal = arr[i];
int maxS = findMaxS(curVal);
int minL = findMinL(curVal);
if (minL != -1 && even[minL]) {
// System.out.println("find minL is true at: "+minL+" start from "+i);
odd[i] = even[minL];
count++;
}
if (maxS != -1) {
even[i] = odd[maxS];
}
valToPos[arr[i]] = i;
}
return count;
}
private int findMaxS(int val) {
for (int i = val; i >= 0; i--) {
if (valToPos[i] != -1) {
return valToPos[i];
}
}
return -1;
}
private int findMinL(int val) {
for (int i = val; i < 100001; i++) {
if (valToPos[i] != -1) {
return valToPos[i];
}
}
return -1;
}
}
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