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package g1001_1100.s1049_last_stone_weight_ii;
// #Medium #Array #Dynamic_Programming #2022_02_28_Time_2_ms_(95.98%)_Space_41.8_MB_(31.51%)
public class Solution {
public int lastStoneWeightII(int[] stones) {
// dp[i][j] i is the index of stones, j is the current weight
// goal is to find max closest to half and use it to get the diff
// 0-1 knapsack problem
int sum = 0;
for (int stone : stones) {
sum += stone;
}
int half = sum / 2;
int[] dp = new int[half + 1];
for (int cur : stones) {
for (int j = half; j >= cur; j--) {
dp[j] = Math.max(dp[j], dp[j - cur] + cur);
}
}
return sum - dp[half] * 2;
}
}
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