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1177\. Can Make Palindrome from Substring
Medium
You are given a string `s` and array `queries` where queries[i] = [lefti, righti, ki]
. We may rearrange the substring s[lefti...righti]
for each query and then choose up to ki
of them to replace with any lowercase English letter.
If the substring is possible to be a palindrome string after the operations above, the result of the query is `true`. Otherwise, the result is `false`.
Return a boolean array `answer` where `answer[i]` is the result of the ith
query `queries[i]`.
Note that each letter is counted individually for replacement, so if, for example s[lefti...righti] = "aaa"
, and ki = 2
, we can only replace two of the letters. Also, note that no query modifies the initial string `s`.
**Example :**
**Input:** s = "abcda", queries = [[3,3,0],[1,2,0],[0,3,1],[0,3,2],[0,4,1]]
**Output:** [true,false,false,true,true]
**Explanation:**
queries[0]: substring = "d", is palidrome.
queries[1]: substring = "bc", is not palidrome.
queries[2]: substring = "abcd", is not palidrome after replacing only 1 character. q
ueries[3]: substring = "abcd", could be changed to "abba" which is palidrome. Also this can be changed to "baab" first rearrange it "bacd" then replace "cd" with "ab".
queries[4]: substring = "abcda", could be changed to "abcba" which is palidrome.
**Example 2:**
**Input:** s = "lyb", queries = [[0,1,0],[2,2,1]]
**Output:** [false,true]
**Constraints:**
* 1 <= s.length, queries.length <= 105
* 0 <= lefti <= righti < s.length
* 0 <= ki <= s.length
* `s` consists of lowercase English letters.
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