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Java-based LeetCode algorithm problem solutions, regularly updated
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1286\. Iterator for Combination
Medium
Design the `CombinationIterator` class:
* `CombinationIterator(string characters, int combinationLength)` Initializes the object with a string `characters` of **sorted distinct** lowercase English letters and a number `combinationLength` as arguments.
* `next()` Returns the next combination of length `combinationLength` in **lexicographical order**.
* `hasNext()` Returns `true` if and only if there exists a next combination.
**Example 1:**
**Input** ["CombinationIterator", "next", "hasNext", "next", "hasNext", "next", "hasNext"] [["abc", 2], [], [], [], [], [], []]
**Output:** [null, "ab", true, "ac", true, "bc", false]
**Explanation:** CombinationIterator itr = new CombinationIterator("abc", 2); itr.next(); // return "ab" itr.hasNext(); // return True itr.next(); // return "ac" itr.hasNext(); // return True itr.next(); // return "bc" itr.hasNext(); // return False
**Constraints:**
* `1 <= combinationLength <= characters.length <= 15`
* All the characters of `characters` are **unique**.
* At most 104
calls will be made to `next` and `hasNext`.
* It is guaranteed that all calls of the function `next` are valid.
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