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Java-based LeetCode algorithm problem solutions, regularly updated
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1306\. Jump Game III
Medium
Given an array of non-negative integers `arr`, you are initially positioned at `start` index of the array. When you are at index `i`, you can jump to `i + arr[i]` or `i - arr[i]`, check if you can reach to **any** index with value 0.
Notice that you can not jump outside of the array at any time.
**Example 1:**
**Input:** arr = [4,2,3,0,3,1,2], start = 5
**Output:** true
**Explanation:**
All possible ways to reach at index 3 with value 0 are:
index 5 -> index 4 -> index 1 -> index 3
index 5 -> index 6 -> index 4 -> index 1 -> index 3
**Example 2:**
**Input:** arr = [4,2,3,0,3,1,2], start = 0
**Output:** true
**Explanation:**
One possible way to reach at index 3 with value 0 is:
index 0 -> index 4 -> index 1 -> index 3
**Example 3:**
**Input:** arr = [3,0,2,1,2], start = 2
**Output:** false
**Explanation:** There is no way to reach at index 1 with value 0.
**Constraints:**
* 1 <= arr.length <= 5 * 104
* `0 <= arr[i] < arr.length`
* `0 <= start < arr.length`
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