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Java-based LeetCode algorithm problem solutions, regularly updated
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1436\. Destination City
Easy
You are given the array `paths`, where paths[i] = [cityAi, cityBi]
means there exists a direct path going from cityAi
to cityBi
. _Return the destination city, that is, the city without any path outgoing to another city._
It is guaranteed that the graph of paths forms a line without any loop, therefore, there will be exactly one destination city.
**Example 1:**
**Input:** paths = [["London","New York"],["New York","Lima"],["Lima","Sao Paulo"]]
**Output:** "Sao Paulo"
**Explanation:** Starting at "London" city you will reach "Sao Paulo" city which is the destination city. Your trip consist of: "London" -> "New York" -> "Lima" -> "Sao Paulo".
**Example 2:**
**Input:** paths = [["B","C"],["D","B"],["C","A"]]
**Output:** "A"
**Explanation:** All possible trips are:
"D" -> "B" -> "C" -> "A".
"B" -> "C" -> "A".
"C" -> "A".
"A". Clearly the destination city is "A".
**Example 3:**
**Input:** paths = [["A","Z"]]
**Output:** "Z"
**Constraints:**
* `1 <= paths.length <= 100`
* `paths[i].length == 2`
* 1 <= cityAi.length, cityBi.length <= 10
* cityAi != cityBi
* All strings consist of lowercase and uppercase English letters and the space character.
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