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Java-based LeetCode algorithm problem solutions, regularly updated
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package g1401_1500.s1473_paint_house_iii;
// #Hard #Array #Dynamic_Programming #2022_03_29_Time_26_ms_(89.13%)_Space_42.9_MB_(91.75%)
public class Solution {
private int[][][] memo;
private int[] houses;
private int nColors;
private int[][] cost;
public int minCost(int[] houses, int[][] cost, int nColors, int tGroups) {
this.cost = cost;
this.houses = houses;
this.memo = new int[houses.length][nColors + 1][tGroups + 1];
this.nColors = nColors;
int dp = dp(0, 0, tGroups);
return dp == Integer.MAX_VALUE ? -1 : dp;
}
private int dp(int ithEl, int prevClr, int tGroups) {
if (ithEl == houses.length) {
return tGroups == 0 ? 0 : Integer.MAX_VALUE;
}
if (ithEl < houses.length && tGroups < 0) {
return Integer.MAX_VALUE;
}
if (memo[ithEl][prevClr][tGroups] == 0) {
int currC = houses[ithEl];
int res = Integer.MAX_VALUE;
if (currC != 0) {
int grpLeft = currC == prevClr ? tGroups : tGroups - 1;
res = dp(ithEl + 1, currC, grpLeft);
} else {
for (int clr = 1; clr <= nColors; clr++) {
int grpLeft = clr == prevClr ? tGroups : tGroups - 1;
int dp = dp(ithEl + 1, clr, grpLeft);
res =
Math.min(
res,
dp != Integer.MAX_VALUE
? cost[ithEl][clr - 1] + dp
: Integer.MAX_VALUE);
}
}
memo[ithEl][prevClr][tGroups] = res;
}
return memo[ithEl][prevClr][tGroups];
}
}
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