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Java-based LeetCode algorithm problem solutions, regularly updated
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package g1401_1500.s1494_parallel_courses_ii;
// #Hard #Dynamic_Programming #Bit_Manipulation #Graph #Bitmask
// #2022_03_23_Time_325_ms_(42.24%)_Space_43.3_MB_(52.43%)
import java.util.Arrays;
public class Solution {
public int minNumberOfSemesters(int n, int[][] relations, int k) {
int[] pres = new int[n];
for (int[] r : relations) {
int prev = r[0] - 1;
int next = r[1] - 1;
pres[next] |= (1 << prev);
}
int[] dp = new int[1 << n];
Arrays.fill(dp, n);
dp[0] = 0;
for (int mask = 0; mask < dp.length; mask++) {
int canTake = 0;
for (int i = 0; i < n; i++) {
// already taken
if ((mask & (1 << i)) != 0) {
continue;
}
// satisfy all pres
if ((mask & pres[i]) == pres[i]) {
canTake |= (1 << i);
}
}
// loop each sub-masks
for (int take = canTake; take > 0; take = (take - 1) & canTake) {
if (Integer.bitCount(take) > k) {
continue;
}
dp[take | mask] = Math.min(dp[take | mask], dp[mask] + 1);
}
}
return dp[(1 << n) - 1];
}
}
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