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1507\. Reformat Date
Easy
Given a `date` string in the form `Day Month Year`, where:
* `Day` is in the set `{"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}`.
* `Month` is in the set `{"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}`.
* `Year` is in the range `[1900, 2100]`.
Convert the date string to the format `YYYY-MM-DD`, where:
* `YYYY` denotes the 4 digit year.
* `MM` denotes the 2 digit month.
* `DD` denotes the 2 digit day.
**Example 1:**
**Input:** date = "20th Oct 2052"
**Output:** "2052-10-20"
**Example 2:**
**Input:** date = "6th Jun 1933"
**Output:** "1933-06-06"
**Example 3:**
**Input:** date = "26th May 1960"
**Output:** "1960-05-26"
**Constraints:**
* The given dates are guaranteed to be valid, so no error handling is necessary.
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