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Java-based LeetCode algorithm problem solutions, regularly updated
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1518\. Water Bottles
Easy
There are `numBottles` water bottles that are initially full of water. You can exchange `numExchange` empty water bottles from the market with one full water bottle.
The operation of drinking a full water bottle turns it into an empty bottle.
Given the two integers `numBottles` and `numExchange`, return _the **maximum** number of water bottles you can drink_.
**Example 1:**
![](https://assets.leetcode.com/uploads/2020/07/01/sample_1_1875.png)
**Input:** numBottles = 9, numExchange = 3
**Output:** 13
**Explanation:** You can exchange 3 empty bottles to get 1 full water bottle. Number of water bottles you can drink: 9 + 3 + 1 = 13.
**Example 2:**
![](https://assets.leetcode.com/uploads/2020/07/01/sample_2_1875.png)
**Input:** numBottles = 15, numExchange = 4
**Output:** 19
**Explanation:** You can exchange 4 empty bottles to get 1 full water bottle. Number of water bottles you can drink: 15 + 3 + 1 = 19.
**Constraints:**
* `1 <= numBottles <= 100`
* `2 <= numExchange <= 100`
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