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package g1701_1800.s1745_palindrome_partitioning_iv;
// #Hard #String #Dynamic_Programming #2022_04_29_Time_10_ms_(100.00%)_Space_44_MB_(95.27%)
public class Solution {
public boolean checkPartitioning(String s) {
final int len = s.length();
char[] ch = s.toCharArray();
int[] dp = new int[len + 1];
dp[0] = 0x01;
for (int i = 0; i < len; i++) {
for (int l : new int[] {i - 1, i}) {
int r = i;
while (l >= 0 && r < len && ch[l] == ch[r]) {
dp[r + 1] |= dp[l] << 1;
l--;
r++;
}
}
}
return (dp[len] & 0x08) == 0x08;
}
}
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