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1912\. Design Movie Rental System
Hard
You have a movie renting company consisting of `n` shops. You want to implement a renting system that supports searching for, booking, and returning movies. The system should also support generating a report of the currently rented movies.
Each movie is given as a 2D integer array `entries` where entries[i] = [shopi, moviei, pricei]
indicates that there is a copy of movie moviei
at shop shopi
with a rental price of pricei
. Each shop carries **at most one** copy of a movie moviei
.
The system should support the following functions:
* **Search**: Finds the **cheapest 5 shops** that have an **unrented copy** of a given movie. The shops should be sorted by **price** in ascending order, and in case of a tie, the one with the **smaller** shopi
should appear first. If there are less than 5 matching shops, then all of them should be returned. If no shop has an unrented copy, then an empty list should be returned.
* **Rent**: Rents an **unrented copy** of a given movie from a given shop.
* **Drop**: Drops off a **previously rented copy** of a given movie at a given shop.
* **Report**: Returns the **cheapest 5 rented movies** (possibly of the same movie ID) as a 2D list `res` where res[j] = [shopj, moviej]
describes that the jth
cheapest rented movie moviej
was rented from the shop shopj
. The movies in `res` should be sorted by **price** in ascending order, and in case of a tie, the one with the **smaller** shopj
should appear first, and if there is still tie, the one with the **smaller** moviej
should appear first. If there are fewer than 5 rented movies, then all of them should be returned. If no movies are currently being rented, then an empty list should be returned.
Implement the `MovieRentingSystem` class:
* `MovieRentingSystem(int n, int[][] entries)` Initializes the `MovieRentingSystem` object with `n` shops and the movies in `entries`.
* `List search(int movie)` Returns a list of shops that have an **unrented copy** of the given `movie` as described above.
* `void rent(int shop, int movie)` Rents the given `movie` from the given `shop`.
* `void drop(int shop, int movie)` Drops off a previously rented `movie` at the given `shop`.
* `List> report()` Returns a list of cheapest **rented** movies as described above.
**Note:** The test cases will be generated such that `rent` will only be called if the shop has an **unrented** copy of the movie, and `drop` will only be called if the shop had **previously rented** out the movie.
**Example 1:**
**Input** ["MovieRentingSystem", "search", "rent", "rent", "report", "drop", "search"] [[3, [[0, 1, 5], [0, 2, 6], [0, 3, 7], [1, 1, 4], [1, 2, 7], [2, 1, 5]]], [1], [0, 1], [1, 2], [], [1, 2], [2]]
**Output:** [null, [1, 0, 2], null, null, [[0, 1], [1, 2]], null, [0, 1]]
**Explanation:** MovieRentingSystem movieRentingSystem = new MovieRentingSystem(3, [[0, 1, 5], [0, 2, 6], [0, 3, 7], [1, 1, 4], [1, 2, 7], [2, 1, 5]]); movieRentingSystem.search(1); // return [1, 0, 2], Movies of ID 1 are unrented at shops 1, 0, and 2. Shop 1 is cheapest; shop 0 and 2 are the same price, so order by shop number. movieRentingSystem.rent(0, 1); // Rent movie 1 from shop 0. Unrented movies at shop 0 are now [2,3]. movieRentingSystem.rent(1, 2); // Rent movie 2 from shop 1. Unrented movies at shop 1 are now [1]. movieRentingSystem.report(); // return [[0, 1], [1, 2]]. Movie 1 from shop 0 is cheapest, followed by movie 2 from shop 1. movieRentingSystem.drop(1, 2); // Drop off movie 2 at shop 1. Unrented movies at shop 1 are now [1,2]. movieRentingSystem.search(2); // return [0, 1]. Movies of ID 2 are unrented at shops 0 and 1. Shop 0 is cheapest, followed by shop 1.
**Constraints:**
* 1 <= n <= 3 * 105
* 1 <= entries.length <= 105
* 0 <= shopi < n
* 1 <= moviei, pricei <= 104
* Each shop carries **at most one** copy of a movie moviei
.
* At most 105
calls **in total** will be made to `search`, `rent`, `drop` and `report`.
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