g2001_2100.s2092_find_all_people_with_secret.Solution Maven / Gradle / Ivy
Go to download
Show more of this group Show more artifacts with this name
Show all versions of leetcode-in-java Show documentation
Show all versions of leetcode-in-java Show documentation
Java-based LeetCode algorithm problem solutions, regularly updated
The newest version!
package g2001_2100.s2092_find_all_people_with_secret;
// #Hard #Sorting #Depth_First_Search #Breadth_First_Search #Graph #Union_Find
// #2022_05_27_Time_95_ms_(84.86%)_Space_99.7_MB_(87.33%)
import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashSet;
import java.util.List;
import java.util.Set;
public class Solution {
public List findAllPeople(int n, int[][] meetings, int firstPerson) {
Arrays.sort(meetings, ((a, b) -> a[2] - b[2]));
UF uf = new UF(n);
// base
uf.union(0, firstPerson);
// for every time we have a pool of people that talk to each other
// if someone knows a secret proir to this meeting - all pool will too
// if not - reset unions from this pool
int i = 0;
while (i < meetings.length) {
int curTime = meetings[i][2];
Set pool = new HashSet<>();
while (i < meetings.length && curTime == meetings[i][2]) {
int[] currentMeeting = meetings[i];
uf.union(currentMeeting[0], currentMeeting[1]);
pool.add(currentMeeting[0]);
pool.add(currentMeeting[1]);
i++;
}
// meeting that took place now should't affect future
// meetings if people don't know the secret
for (int j : pool) {
if (!uf.connected(0, j)) {
uf.reset(j);
}
}
}
// if the person is conneted to 0 - they know a secret
List ans = new ArrayList<>();
for (int j = 0; j < n; j++) {
if (uf.connected(j, 0)) {
ans.add(j);
}
}
return ans;
}
// regular union find
private static class UF {
private int[] parent;
private int[] rank;
public UF(int n) {
parent = new int[n];
rank = new int[n];
for (int i = 0; i < n; i++) {
parent[i] = i;
}
}
public void union(int p, int q) {
int rootP = find(p);
int rootQ = find(q);
if (rootP == rootQ) {
return;
}
if (rank[rootP] < rank[rootQ]) {
parent[rootP] = rootQ;
} else {
parent[rootQ] = rootP;
rank[rootP]++;
}
}
public int find(int p) {
while (parent[p] != p) {
p = parent[parent[p]];
}
return p;
}
public boolean connected(int p, int q) {
return find(p) == find(q);
}
public void reset(int p) {
parent[p] = p;
rank[p] = 0;
}
}
}
© 2015 - 2024 Weber Informatics LLC | Privacy Policy