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2295\. Replace Elements in an Array

Medium

You are given a **0-indexed** array `nums` that consists of `n` **distinct** positive integers. Apply `m` operations to this array, where in the ith operation you replace the number `operations[i][0]` with `operations[i][1]`.

It is guaranteed that in the ith operation:

*   `operations[i][0]` **exists** in `nums`.
*   `operations[i][1]` does **not** exist in `nums`.

Return _the array obtained after applying all the operations_.

**Example 1:**

**Input:** nums = [1,2,4,6], operations = [[1,3],[4,7],[6,1]]

**Output:** [3,2,7,1]

**Explanation:**

We perform the following operations on nums: 

- Replace the number 1 with 3. nums becomes [**3**,2,4,6]. 

- Replace the number 4 with 7. nums becomes [3,2,**7**,6]. 

- Replace the number 6 with 1. nums becomes [3,2,7,**1**]. 

We return the final array [3,2,7,1]. 

**Example 2:**

**Input:** nums = [1,2], operations = [[1,3],[2,1],[3,2]]

**Output:** [2,1]

**Explanation:**

We perform the following operations to nums: 

- Replace the number 1 with 3. nums becomes [**3**,2]. 
 
- Replace the number 2 with 1. nums becomes [3,**1**]. 

- Replace the number 3 with 2. nums becomes [**2**,1]. 

We return the array [2,1]. 

**Constraints:**

*   `n == nums.length`
*   `m == operations.length`
*   1 <= n, m <= 105
*   All the values of `nums` are **distinct**.
*   `operations[i].length == 2`
*   1 <= nums[i], operations[i][0], operations[i][1] <= 106
*   `operations[i][0]` will exist in `nums` when applying the ith operation.
*   `operations[i][1]` will not exist in `nums` when applying the ith operation.




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