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package g2301_2400.s2301_match_substring_after_replacement;
// #Hard #Array #String #Hash_Table #String_Matching
// #2022_06_16_Time_205_ms_(94.20%)_Space_52.1_MB_(54.60%)
import java.util.HashSet;
import java.util.Set;
@SuppressWarnings("unchecked")
public class Solution {
private char[] c1;
private char[] c2;
private Set[] al;
public boolean matchReplacement(String s, String sub, char[][] mappings) {
c1 = s.toCharArray();
c2 = sub.toCharArray();
al = new Set[75];
for (int i = 0; i < 75; i++) {
Set temp = new HashSet<>();
al[i] = temp;
}
for (char[] mapping : mappings) {
al[mapping[0] - '0'].add(mapping[1]);
}
return ans(c1.length, c2.length) == 1;
}
private int ans(int m, int n) {
if (m == 0) {
return 0;
}
if (ans(m - 1, n) == 1) {
return 1;
}
if (m >= n && (c1[m - 1] == c2[n - 1] || al[c2[n - 1] - '0'].contains(c1[m - 1]))) {
while (n >= 1 && (c1[m - 1] == c2[n - 1] || al[c2[n - 1] - '0'].contains(c1[m - 1]))) {
n--;
m--;
}
if (n == 0) {
return 1;
}
}
return 0;
}
}
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