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Java-based LeetCode algorithm problem solutions, regularly updated
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package g2301_2400.s2306_naming_a_company;
// #Hard #Array #String #Hash_Table #Bit_Manipulation #Enumeration
// #2022_06_15_Time_486_ms_(74.14%)_Space_83.3_MB_(58.98%)
import java.util.HashMap;
import java.util.HashSet;
import java.util.Map;
import java.util.Set;
public class Solution {
private long count(Map> map, char a, char b) {
if (!map.containsKey(a) || !map.containsKey(b)) {
return 0;
}
long common = 0;
Set first = map.get(a);
Set second = map.get(b);
for (String c : first) {
if (second.contains(c)) {
common++;
}
}
long uniqueA = first.size() - common;
long uniqueB = second.size() - common;
return uniqueA * uniqueB * 2L;
}
public long distinctNames(String[] ideas) {
long ans = 0;
Map> map = new HashMap<>();
for (String idea : ideas) {
char startChar = idea.charAt(0);
Set values = map.getOrDefault(startChar, new HashSet<>());
values.add(idea.substring(1));
map.put(startChar, values);
}
for (int i = 0; i <= 26; i++) {
for (int j = i + 1; j <= 26; j++) {
long unique = count(map, (char) (i + 'a'), (char) (j + 'a'));
ans += unique;
}
}
return ans;
}
}
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