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package g2301_2400.s2318_number_of_distinct_roll_sequences;
// #Hard #Dynamic_Programming #Memoization #2022_06_26_Time_254_ms_(91.67%)_Space_51.6_MB_(58.33%)
public class Solution {
private int[][][] memo = new int[10001][7][7];
private int mod = 1000000007;
private int[][] m = {
{1, 2, 3, 4, 5, 6},
{2, 3, 4, 5, 6},
{1, 3, 5},
{1, 2, 4, 5},
{1, 3, 5},
{1, 2, 3, 4, 6},
{1, 5}
};
public int distinctSequences(int n) {
return dp(n, 0, 0);
}
private int dp(int n, int prev, int pprev) {
if (n == 0) {
return 1;
}
if (memo[n][prev][pprev] != 0) {
return memo[n][prev][pprev];
}
int ans = 0;
for (int x : m[prev]) {
if (x != pprev) {
ans = (ans + dp(n - 1, x, prev)) % mod;
}
}
memo[n][prev][pprev] = ans;
return ans;
}
}
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