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package g2401_2500.s2426_number_of_pairs_satisfying_inequality;
// #Hard #Array #Binary_Search #Ordered_Set #Divide_and_Conquer #Segment_Tree #Binary_Indexed_Tree
// #Merge_Sort #2022_11_19_Time_12_ms_(99.69%)_Space_60.6_MB_(86.02%)
public class Solution {
private long[] cnt;
private long find(int x, int n) {
long res = 0;
x = Math.min(x, n);
while (x > 0) {
res += cnt[x];
x -= (x & (-x));
}
return res;
}
private void update(int x, int n) {
while (x <= n) {
cnt[x] += 1;
x += (x & (-x));
}
}
public long numberOfPairs(int[] nums1, int[] nums2, int diff) {
int n = nums1.length;
int[] nums = new int[n];
int min = Integer.MAX_VALUE;
int max = Integer.MIN_VALUE;
for (int i = 0; i < n; i++) {
nums[i] = nums1[i] - nums2[i];
min = Math.min(min, nums[i]);
max = Math.max(max, nums[i]);
}
max = max - min + 2;
long ans = 0;
cnt = new long[50000];
for (int i = 0; i < n; i++) {
nums[i] = nums[i] - min + 1;
ans += find(nums[i] + diff, max);
update(nums[i], max);
}
return ans;
}
}
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