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Java-based LeetCode algorithm problem solutions, regularly updated
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2485\. Find the Pivot Integer
Easy
Given a positive integer `n`, find the **pivot integer** `x` such that:
* The sum of all elements between `1` and `x` inclusively equals the sum of all elements between `x` and `n` inclusively.
Return _the pivot integer_ `x`. If no such integer exists, return `-1`. It is guaranteed that there will be at most one pivot index for the given input.
**Example 1:**
**Input:** n = 8
**Output:** 6
**Explanation:** 6 is the pivot integer since: 1 + 2 + 3 + 4 + 5 + 6 = 6 + 7 + 8 = 21.
**Example 2:**
**Input:** n = 1
**Output:** 1
**Explanation:** 1 is the pivot integer since: 1 = 1.
**Example 3:**
**Input:** n = 4
**Output:** -1
**Explanation:** It can be proved that no such integer exist.
**Constraints:**
* `1 <= n <= 1000`
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