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package g2501_2600.s2518_number_of_great_partitions;
// #Hard #Array #Dynamic_Programming #2023_04_18_Time_4_ms_(100.00%)_Space_41.4_MB_(98.28%)
public class Solution {
private static final int MOD = 1000000007;
public int countPartitions(int[] nums, int k) {
// edge cases
int n = nums.length;
long sum = 0;
for (int num : nums) {
sum += num;
}
if (sum < 2L * k) {
return 0;
}
// normal cases
int[] dp = new int[k];
dp[0] = 1;
for (int num : nums) {
for (int i = k - 1; i >= num; i--) {
dp[i] = (dp[i] + dp[i - num]) % MOD;
}
}
int smaller = 0;
for (int i = 0; i < k; i++) {
smaller = (smaller + dp[i]) % MOD;
}
return (pow(2, n) - (smaller * 2) % MOD + MOD) % MOD;
}
private int pow(long num, int pow) {
long result = 1;
while (pow != 0) {
if (pow % 2 == 1) {
result = (result * num) % MOD;
}
pow /= 2;
num = (num * num) % MOD;
}
return (int) result;
}
}
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