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Java-based LeetCode algorithm problem solutions, regularly updated
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2574\. Left and Right Sum Differences
Easy
Given a **0-indexed** integer array `nums`, find a **0-indexed** integer array `answer` where:
* `answer.length == nums.length`.
* `answer[i] = |leftSum[i] - rightSum[i]|`.
Where:
* `leftSum[i]` is the sum of elements to the left of the index `i` in the array `nums`. If there is no such element, `leftSum[i] = 0`.
* `rightSum[i]` is the sum of elements to the right of the index `i` in the array `nums`. If there is no such element, `rightSum[i] = 0`.
Return _the array_ `answer`.
**Example 1:**
**Input:** nums = [10,4,8,3]
**Output:** [15,1,11,22]
**Explanation:** The array leftSum is [0,10,14,22] and the array rightSum is [15,11,3,0]. The array answer is [|0 - 15|,|10 - 11|,|14 - 3|,|22 - 0|] = [15,1,11,22].
**Example 2:**
**Input:** nums = [1]
**Output:** [0]
**Explanation:** The array leftSum is [0] and the array rightSum is [0]. The array answer is [|0 - 0|] = [0].
**Constraints:**
* `1 <= nums.length <= 1000`
* 1 <= nums[i] <= 105
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