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2924\. Find Champion II

Medium

There are `n` teams numbered from `0` to `n - 1` in a tournament; each team is also a node in a **DAG**.

You are given the integer `n` and a **0-indexed** 2D integer array `edges` of length `m` representing the **DAG**, where edges[i] = [ui, vi] indicates that there is a directed edge from team ui to team vi in the graph.

A directed edge from `a` to `b` in the graph means that team `a` is **stronger** than team `b` and team `b` is **weaker** than team `a`.

Team `a` will be the **champion** of the tournament if there is no team `b` that is **stronger** than team `a`.

Return _the team that will be the **champion** of the tournament if there is a **unique** champion, otherwise, return_ `-1`_._

**Notes**

*   A **cycle** is a series of nodes a1, a2, ..., an, an+1 such that node a1 is the same node as node an+1, the nodes a1, a2, ..., an are distinct, and there is a directed edge from the node ai to node ai+1 for every `i` in the range `[1, n]`.
*   A **DAG** is a directed graph that does not have any **cycle**.

**Example 1:**

![](https://assets.leetcode.com/uploads/2023/10/19/graph-3.png)

**Input:** n = 3, edges = [[0,1],[1,2]]

**Output:** 0

**Explanation:** Team 1 is weaker than team 0. Team 2 is weaker than team 1. So the champion is team 0.

**Example 2:**

![](https://assets.leetcode.com/uploads/2023/10/19/graph-4.png)

**Input:** n = 4, edges = [[0,2],[1,3],[1,2]]

**Output:** -1

**Explanation:** Team 2 is weaker than team 0 and team 1. Team 3 is weaker than team 1. But team 1 and team 0 are not weaker than any other teams. So the answer is -1.

**Constraints:**

*   `1 <= n <= 100`
*   `m == edges.length`
*   `0 <= m <= n * (n - 1) / 2`
*   `edges[i].length == 2`
*   `0 <= edge[i][j] <= n - 1`
*   `edges[i][0] != edges[i][1]`
*   The input is generated such that if team `a` is stronger than team `b`, team `b` is not stronger than team `a`.
*   The input is generated such that if team `a` is stronger than team `b` and team `b` is stronger than team `c`, then team `a` is stronger than team `c`.




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