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Java-based LeetCode algorithm problem solutions, regularly updated
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package g2901_3000.s2933_high_access_employees;
// #Medium #Array #String #Hash_Table #Sorting #2024_01_02_Time_9_ms_(87.94%)_Space_45.6_MB_(5.79%)
import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class Solution {
private boolean isPossible(int a, int b) {
int hb = b / 100;
int ha = a / 100;
int mind = b % 100;
int mina = a % 100;
if (hb == 23 && ha == 0) {
return false;
}
if (hb - ha > 1) {
return false;
}
if (hb - ha == 1) {
mind += 60;
}
return mind - mina < 60;
}
private boolean isHighAccess(List list) {
if (list.size() < 3) {
return false;
}
int i = 0;
int j = 1;
int k = 2;
while (k < list.size()) {
int a = list.get(i++);
int b = list.get(j++);
int c = list.get(k++);
if (isPossible(a, c) && isPossible(b, c) && isPossible(a, b)) {
return true;
}
}
return false;
}
private int stringToInt(String str) {
int i = 1000;
int val = 0;
for (char ch : str.toCharArray()) {
int n = ch - '0';
val += i * n;
i = i / 10;
}
return val;
}
public List findHighAccessEmployees(List> accessTimes) {
HashMap> map = new HashMap<>();
for (List list : accessTimes) {
List temp = map.getOrDefault(list.get(0), new ArrayList<>());
int val = stringToInt(list.get(1));
temp.add(val);
map.put(list.get(0), temp);
}
List ans = new ArrayList<>();
for (Map.Entry> entry : map.entrySet()) {
List temp = entry.getValue();
Collections.sort(temp);
if (isHighAccess(temp)) {
ans.add(entry.getKey());
}
}
return ans;
}
}
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