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package g2901_3000.s2949_count_beautiful_substrings_ii;
// #Hard #String #Hash_Table #Math #Prefix_Sum #Number_Theory
// #2023_12_26_Time_29_ms_(92.10%)_Space_46_MB_(37.13%)
import java.util.HashMap;
@SuppressWarnings("unchecked")
public class Solution {
public long beautifulSubstrings(String s, int k) {
long res = 0;
int n = s.length();
int l = 1;
while ((l * l) % (4 * k) != 0) {
l++;
}
HashMap[] seen = new HashMap[l];
for (int i = 0; i < l; ++i) {
seen[i] = new HashMap<>();
}
int v = 0;
seen[l - 1].put(0, 1);
for (int i = 0; i < n; ++i) {
char c = s.charAt(i);
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u') {
v += 1;
} else {
v -= 1;
}
int cnt = seen[i % l].getOrDefault(v, 0);
res += cnt;
seen[i % l].put(v, cnt + 1);
}
return res;
}
}
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