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Java-based LeetCode algorithm problem solutions, regularly updated

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3142\. Check if Grid Satisfies Conditions

Easy

You are given a 2D matrix `grid` of size `m x n`. You need to check if each cell `grid[i][j]` is:

*   Equal to the cell below it, i.e. `grid[i][j] == grid[i + 1][j]` (if it exists).
*   Different from the cell to its right, i.e. `grid[i][j] != grid[i][j + 1]` (if it exists).

Return `true` if **all** the cells satisfy these conditions, otherwise, return `false`.

**Example 1:**

**Input:** grid = [[1,0,2],[1,0,2]]

**Output:** true

**Explanation:**

**![](https://assets.leetcode.com/uploads/2024/04/15/examplechanged.png)**

All the cells in the grid satisfy the conditions.

**Example 2:**

**Input:** grid = [[1,1,1],[0,0,0]]

**Output:** false

**Explanation:**

**![](https://assets.leetcode.com/uploads/2024/03/27/example21.png)**

All cells in the first row are equal.

**Example 3:**

**Input:** grid = [[1],[2],[3]]

**Output:** false

**Explanation:**

![](https://assets.leetcode.com/uploads/2024/03/31/changed.png)

Cells in the first column have different values.

**Constraints:**

*   `1 <= n, m <= 10`
*   `0 <= grid[i][j] <= 9`