g0001_0100.s0006_zigzag_conversion.Solution Maven / Gradle / Ivy
package g0001_0100.s0006_zigzag_conversion;
// #Medium #String #2022_06_13_Time_3_ms_(98.64%)_Space_42.5_MB_(95.79%)
/**
* 6 - Zigzag Conversion\.
*
* Medium
*
* The string `"PAYPALISHIRING"` is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
*
* P A H N A P L S I I G Y I R
*
* And then read line by line: `"PAHNAPLSIIGYIR"`
*
* Write the code that will take a string and make this conversion given a number of rows:
*
* string convert(string s, int numRows);
*
* **Example 1:**
*
* **Input:** s = "PAYPALISHIRING", numRows = 3
*
* **Output:** "PAHNAPLSIIGYIR"
*
* **Example 2:**
*
* **Input:** s = "PAYPALISHIRING", numRows = 4
*
* **Output:** "PINALSIGYAHRPI"
*
* **Explanation:** P I N A L S I G Y A H R P I
*
* **Example 3:**
*
* **Input:** s = "A", numRows = 1
*
* **Output:** "A"
*
* **Constraints:**
*
* * `1 <= s.length <= 1000`
* * `s` consists of English letters (lower-case and upper-case), `','` and `'.'`.
* * `1 <= numRows <= 1000`
**/
public class Solution {
public String convert(String s, int numRows) {
int sLen = s.length();
if (numRows == 1) {
return s;
}
int maxDist = numRows * 2 - 2;
StringBuilder buf = new StringBuilder();
for (int i = 0; i < numRows; i++) {
int index = i;
if (i == 0 || i == numRows - 1) {
while (index < sLen) {
buf.append(s.charAt(index));
index += maxDist;
}
} else {
while (index < sLen) {
buf.append(s.charAt(index));
index += maxDist - i * 2;
if (index >= sLen) {
break;
}
buf.append(s.charAt(index));
index += i * 2;
}
}
}
return buf.toString();
}
}
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