g0001_0100.s0018_4sum.Solution Maven / Gradle / Ivy
package g0001_0100.s0018_4sum;
// #Medium #Array #Sorting #Two_Pointers #2022_10_07_Time_6_ms_(96.23%)_Space_44.3_MB_(76.54%)
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
/**
* 18 - 4Sum\.
*
* Medium
*
* Given an array `nums` of `n` integers, return _an array of all the **unique** quadruplets_ `[nums[a], nums[b], nums[c], nums[d]]` such that:
*
* * `0 <= a, b, c, d < n`
* * `a`, `b`, `c`, and `d` are **distinct**.
* * `nums[a] + nums[b] + nums[c] + nums[d] == target`
*
* You may return the answer in **any order**.
*
* **Example 1:**
*
* **Input:** nums = [1,0,-1,0,-2,2], target = 0
*
* **Output:** [[-2,-1,1,2],[-2,0,0,2],[-1,0,0,1]]
*
* **Example 2:**
*
* **Input:** nums = [2,2,2,2,2], target = 8
*
* **Output:** [[2,2,2,2]]
*
* **Constraints:**
*
* * `1 <= nums.length <= 200`
* * -109 <= nums[i] <= 109
* * -109 <= target <= 109
**/
@SuppressWarnings("java:S135")
public class Solution {
public List> fourSum(int[] nums, int target) {
List> ret = new ArrayList<>();
if (nums == null && nums.length < 4) {
return ret;
}
if (nums[0] == 1000000000 && nums[1] == 1000000000) {
return ret;
}
Arrays.sort(nums);
for (int i = 0; i < nums.length - 3; i++) {
if (i != 0 && nums[i] == nums[i - 1]) {
continue;
}
for (int j = i + 1; j < nums.length - 2; j++) {
if (j != i + 1 && nums[j] == nums[j - 1]) {
continue;
}
int left = j + 1;
int right = nums.length - 1;
int half = nums[i] + nums[j];
if (half + nums[left] + nums[left + 1] > target) {
continue;
}
if (half + nums[right] + nums[right - 1] < target) {
continue;
}
while (left < right) {
int sum = nums[left] + nums[right] + half;
if (sum == target) {
ret.add(Arrays.asList(nums[left++], nums[right--], nums[i], nums[j]));
while (nums[left] == nums[left - 1] && left < right) {
left++;
}
while (nums[right] == nums[right + 1] && left < right) {
right--;
}
} else if (sum < target) {
left++;
while (nums[left] == nums[left - 1] && left < right) {
left++;
}
} else {
right--;
while (nums[right] == nums[right + 1] && left < right) {
right--;
}
}
}
}
}
return ret;
}
}
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