g0001_0100.s0029_divide_two_integers.Solution Maven / Gradle / Ivy
package g0001_0100.s0029_divide_two_integers;
// #Medium #Top_Interview_Questions #Math #Bit_Manipulation #Udemy_Bit_Manipulation
// #2022_06_14_Time_1_ms_(99.96%)_Space_39.6_MB_(87.25%)
/**
* 29 - Divide Two Integers\.
*
* Medium
*
* Given two integers `dividend` and `divisor`, divide two integers **without** using multiplication, division, and mod operator.
*
* The integer division should truncate toward zero, which means losing its fractional part. For example, `8.345` would be truncated to `8`, and `-2.7335` would be truncated to `-2`.
*
* Return _the **quotient** after dividing_ `dividend` _by_ `divisor`.
*
* **Note:** Assume we are dealing with an environment that could only store integers within the **32-bit** signed integer range: [−231, 231 − 1]. For this problem, if the quotient is **strictly greater than** [231 − 1], then return [231 − 1], and if the quotient is **strictly less than** [-231 − 1], then return [-231 − 1].
*
* **Example 1:**
*
* **Input:** dividend = 10, divisor = 3
*
* **Output:** 3
*
* **Explanation:** 10/3 = 3.33333.. which is truncated to 3.
*
* **Example 2:**
*
* **Input:** dividend = 7, divisor = -3
*
* **Output:** -2
*
* **Explanation:** 7/-3 = -2.33333.. which is truncated to -2.
*
* **Example 3:**
*
* **Input:** dividend = 0, divisor = 1
*
* **Output:** 0
*
* **Example 4:**
*
* **Input:** dividend = 1, divisor = 1
*
* **Output:** 1
*
* **Constraints:**
*
* * -231 <= dividend, divisor <= 231 - 1
* * `divisor != 0`
**/
public class Solution {
public int divide(int dividend, int divisor) {
boolean isNegative = dividend > 0 && divisor < 0 || dividend < 0 && divisor > 0;
long ans = 0;
long divide = Math.abs((long) dividend);
long divisorAbs = Math.abs((long) divisor);
while (divide >= divisorAbs) {
long temp = divisorAbs;
long cnt = 1;
while (divide >= temp) {
divide -= temp;
ans += cnt;
cnt <<= 1;
temp <<= 1;
}
}
if (isNegative) {
ans = -ans;
}
int intMin = -(1 << 31);
int intMax = (1 << 31) - 1;
if (ans < intMin || ans > intMax) {
ans = intMax;
}
return (int) ans;
}
}
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