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g0801_0900.s0802_find_eventual_safe_states.readme.md Maven / Gradle / Ivy

802\. Find Eventual Safe States

Medium

There is a directed graph of `n` nodes with each node labeled from `0` to `n - 1`. The graph is represented by a **0-indexed** 2D integer array `graph` where `graph[i]` is an integer array of nodes adjacent to node `i`, meaning there is an edge from node `i` to each node in `graph[i]`.

A node is a **terminal node** if there are no outgoing edges. A node is a **safe node** if every possible path starting from that node leads to a **terminal node**.

Return _an array containing all the **safe nodes** of the graph_. The answer should be sorted in **ascending** order.

**Example 1:**

![Illustration of graph](https://s3-lc-upload.s3.amazonaws.com/uploads/2018/03/17/picture1.png)

**Input:** graph = [[1,2],[2,3],[5],[0],[5],[],[]]

**Output:** [2,4,5,6]

**Explanation:** The given graph is shown above. 

Nodes 5 and 6 are terminal nodes as there are no outgoing edges from either of them. 

Every path starting at nodes 2, 4, 5, and 6 all lead to either node 5 or 6.

**Example 2:**

**Input:** graph = [[1,2,3,4],[1,2],[3,4],[0,4],[]]

**Output:** [4]

**Explanation:** Only node 4 is a terminal node, and every path starting at node 4 leads to node 4.

**Constraints:**

*   `n == graph.length`
*   1 <= n <= 104
*   `0 <= graph[i].length <= n`
*   `0 <= graph[i][j] <= n - 1`
*   `graph[i]` is sorted in a strictly increasing order.
*   The graph may contain self-loops.
*   The number of edges in the graph will be in the range [1, 4 * 104].