• Home
• com.github.javadev
• leetcode-in-java11
• 1.19
• source code
• readme.md

×

Project download

Many resources are needed to download a project. Please understand that we have to compensate our server costs. Thank you in advance.
Project price only 1 $

You can buy this project and download/modify it how often you want.

g0801_0900.s0813_largest_sum_of_averages.readme.md Maven / Gradle / Ivy

813\. Largest Sum of Averages

Medium

You are given an integer array `nums` and an integer `k`. You can partition the array into **at most** `k` non-empty adjacent subarrays. The **score** of a partition is the sum of the averages of each subarray.

Note that the partition must use every integer in `nums`, and that the score is not necessarily an integer.

Return _the maximum **score** you can achieve of all the possible partitions_. Answers within 10-6 of the actual answer will be accepted.

**Example 1:**

**Input:** nums = [9,1,2,3,9], k = 3

**Output:** 20.00000

**Explanation:** 

The best choice is to partition nums into [9], [1, 2, 3], [9]. The answer is 9 + (1 + 2 + 3) / 3 + 9 = 20. 

We could have also partitioned nums into [9, 1], [2], [3, 9], for example. 

That partition would lead to a score of 5 + 2 + 6 = 13, which is worse.

**Example 2:**

**Input:** nums = [1,2,3,4,5,6,7], k = 4

**Output:** 20.50000

**Constraints:**

*   `1 <= nums.length <= 100`
*   1 <= nums[i] <= 104
*   `1 <= k <= nums.length`