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Java Solution for LeetCode algorithm problems, continually updating
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836\. Rectangle Overlap
Easy
An axis-aligned rectangle is represented as a list `[x1, y1, x2, y2]`, where `(x1, y1)` is the coordinate of its bottom-left corner, and `(x2, y2)` is the coordinate of its top-right corner. Its top and bottom edges are parallel to the X-axis, and its left and right edges are parallel to the Y-axis.
Two rectangles overlap if the area of their intersection is **positive**. To be clear, two rectangles that only touch at the corner or edges do not overlap.
Given two axis-aligned rectangles `rec1` and `rec2`, return `true` _if they overlap, otherwise return_ `false`.
**Example 1:**
**Input:** rec1 = [0,0,2,2], rec2 = [1,1,3,3]
**Output:** true
**Example 2:**
**Input:** rec1 = [0,0,1,1], rec2 = [1,0,2,1]
**Output:** false
**Example 3:**
**Input:** rec1 = [0,0,1,1], rec2 = [2,2,3,3]
**Output:** false
**Constraints:**
* `rect1.length == 4`
* `rect2.length == 4`
* -109 <= rec1[i], rec2[i] <= 109
* `rec1` and `rec2` represent a valid rectangle with a non-zero area.