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Java Solution for LeetCode algorithm problems, continually updating
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882\. Reachable Nodes In Subdivided Graph
Hard
You are given an undirected graph (the **"original graph"**) with `n` nodes labeled from `0` to `n - 1`. You decide to **subdivide** each edge in the graph into a chain of nodes, with the number of new nodes varying between each edge.
The graph is given as a 2D array of `edges` where edges[i] = [ui, vi, cnti]
indicates that there is an edge between nodes ui
and vi
in the original graph, and cnti
is the total number of new nodes that you will **subdivide** the edge into. Note that cnti == 0
means you will not subdivide the edge.
To **subdivide** the edge [ui, vi]
, replace it with (cnti + 1)
new edges and cnti
new nodes. The new nodes are x1
, x2
, ..., xcnti
, and the new edges are [ui, x1]
, [x1, x2]
, [x2, x3]
, ..., [xcnti-1, xcnti]
, [xcnti, vi]
.
In this **new graph**, you want to know how many nodes are **reachable** from the node `0`, where a node is **reachable** if the distance is `maxMoves` or less.
Given the original graph and `maxMoves`, return _the number of nodes that are **reachable** from node_ `0` _in the new graph_.
**Example 1:**
![](https://s3-lc-upload.s3.amazonaws.com/uploads/2018/08/01/origfinal.png)
**Input:** edges = [[0,1,10],[0,2,1],[1,2,2]], maxMoves = 6, n = 3
**Output:** 13
**Explanation:** The edge subdivisions are shown in the image above. The nodes that are reachable are highlighted in yellow.
**Example 2:**
**Input:** edges = [[0,1,4],[1,2,6],[0,2,8],[1,3,1]], maxMoves = 10, n = 4
**Output:** 23
**Example 3:**
**Input:** edges = [[1,2,4],[1,4,5],[1,3,1],[2,3,4],[3,4,5]], maxMoves = 17, n = 5
**Output:** 1
**Explanation:** Node 0 is disconnected from the rest of the graph, so only node 0 is reachable.
**Constraints:**
* 0 <= edges.length <= min(n * (n - 1) / 2, 104)
* `edges[i].length == 3`
* 0 <= ui < vi < n
* There are **no multiple edges** in the graph.
* 0 <= cnti <= 104
* 0 <= maxMoves <= 109
* `1 <= n <= 3000`