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Java Solution for LeetCode algorithm problems, continually updating
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915\. Partition Array into Disjoint Intervals
Medium
Given an integer array `nums`, partition it into two (contiguous) subarrays `left` and `right` so that:
* Every element in `left` is less than or equal to every element in `right`.
* `left` and `right` are non-empty.
* `left` has the smallest possible size.
Return _the length of_ `left` _after such a partitioning_.
Test cases are generated such that partitioning exists.
**Example 1:**
**Input:** nums = [5,0,3,8,6]
**Output:** 3
**Explanation:** left = [5,0,3], right = [8,6]
**Example 2:**
**Input:** nums = [1,1,1,0,6,12]
**Output:** 4
**Explanation:** left = [1,1,1,0], right = [6,12]
**Constraints:**
* 2 <= nums.length <= 105
* 0 <= nums[i] <= 106
* There is at least one valid answer for the given input.