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Java Solution for LeetCode algorithm problems, continually updating
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927\. Three Equal Parts
Hard
You are given an array `arr` which consists of only zeros and ones, divide the array into **three non-empty parts** such that all of these parts represent the same binary value.
If it is possible, return any `[i, j]` with `i + 1 < j`, such that:
* `arr[0], arr[1], ..., arr[i]` is the first part,
* `arr[i + 1], arr[i + 2], ..., arr[j - 1]` is the second part, and
* `arr[j], arr[j + 1], ..., arr[arr.length - 1]` is the third part.
* All three parts have equal binary values.
If it is not possible, return `[-1, -1]`.
Note that the entire part is used when considering what binary value it represents. For example, `[1,1,0]` represents `6` in decimal, not `3`. Also, leading zeros **are allowed**, so `[0,1,1]` and `[1,1]` represent the same value.
**Example 1:**
**Input:** arr = [1,0,1,0,1]
**Output:** [0,3]
**Example 2:**
**Input:** arr = [1,1,0,1,1]
**Output:** [-1,-1]
**Example 3:**
**Input:** arr = [1,1,0,0,1]
**Output:** [0,2]
**Constraints:**
* 3 <= arr.length <= 3 * 104
* `arr[i]` is `0` or `1`