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g0901_1000.s0993_cousins_in_binary_tree.readme.md Maven / Gradle / Ivy

993\. Cousins in Binary Tree

Easy

Given the `root` of a binary tree with unique values and the values of two different nodes of the tree `x` and `y`, return `true` _if the nodes corresponding to the values_ `x` _and_ `y` _in the tree are **cousins**, or_ `false` _otherwise._

Two nodes of a binary tree are **cousins** if they have the same depth with different parents.

Note that in a binary tree, the root node is at the depth `0`, and children of each depth `k` node are at the depth `k + 1`.

**Example 1:**

![](https://assets.leetcode.com/uploads/2019/02/12/q1248-01.png)

**Input:** root = [1,2,3,4], x = 4, y = 3

**Output:** false

**Example 2:**

![](https://assets.leetcode.com/uploads/2019/02/12/q1248-02.png)

**Input:** root = [1,2,3,null,4,null,5], x = 5, y = 4

**Output:** true

**Example 3:**

![](https://assets.leetcode.com/uploads/2019/02/13/q1248-03.png)

**Input:** root = [1,2,3,null,4], x = 2, y = 3

**Output:** false

**Constraints:**

*   The number of nodes in the tree is in the range `[2, 100]`.
*   `1 <= Node.val <= 100`
*   Each node has a **unique** value.
*   `x != y`
*   `x` and `y` are exist in the tree.