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Java Solution for LeetCode algorithm problems, continually updating
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1499\. Max Value of Equation
Hard
You are given an array `points` containing the coordinates of points on a 2D plane, sorted by the x-values, where points[i] = [xi, yi]
such that xi < xj
for all `1 <= i < j <= points.length`. You are also given an integer `k`.
Return _the maximum value of the equation_ yi + yj + |xi - xj|
where |xi - xj| <= k
and `1 <= i < j <= points.length`.
It is guaranteed that there exists at least one pair of points that satisfy the constraint |xi - xj| <= k
.
**Example 1:**
**Input:** points = [[1,3],[2,0],[5,10],[6,-10]], k = 1
**Output:** 4
**Explanation:** The first two points satisfy the condition |xi - xj| <= 1 and if we calculate the equation we get 3 + 0 + |1 - 2| = 4. Third and fourth points also satisfy the condition and give a value of 10 + -10 + |5 - 6| = 1.
No other pairs satisfy the condition, so we return the max of 4 and 1.
**Example 2:**
**Input:** points = [[0,0],[3,0],[9,2]], k = 3
**Output:** 3
**Explanation:** Only the first two points have an absolute difference of 3 or less in the x-values, and give the value of 0 + 0 + |0 - 3| = 3.
**Constraints:**
* 2 <= points.length <= 105
* `points[i].length == 2`
* -108 <= xi, yi <= 108
* 0 <= k <= 2 * 108
* xi < xj
for all `1 <= i < j <= points.length`
* xi
form a strictly increasing sequence.