• Home
• com.github.javadev
• leetcode-in-java11
• 1.19
• source code
• readme.md

×

Project download

Many resources are needed to download a project. Please understand that we have to compensate our server costs. Thank you in advance.
Project price only 1 $

You can buy this project and download/modify it how often you want.

g2001_2100.s2094_finding_3_digit_even_numbers.readme.md Maven / Gradle / Ivy

2094\. Finding 3-Digit Even Numbers

Easy

You are given an integer array `digits`, where each element is a digit. The array may contain duplicates.

You need to find **all** the **unique** integers that follow the given requirements:

*   The integer consists of the **concatenation** of **three** elements from `digits` in **any** arbitrary order.
*   The integer does not have **leading zeros**.
*   The integer is **even**.

For example, if the given `digits` were `[1, 2, 3]`, integers `132` and `312` follow the requirements.

Return _a **sorted** array of the unique integers._

**Example 1:**

**Input:** digits = [2,1,3,0]

**Output:** [102,120,130,132,210,230,302,310,312,320]

**Explanation:** All the possible integers that follow the requirements are in the output array.

Notice that there are no **odd** integers or integers with **leading zeros**. 

**Example 2:**

**Input:** digits = [2,2,8,8,2]

**Output:** [222,228,282,288,822,828,882]

**Explanation:** The same digit can be used as many times as it appears in digits.

In this example, the digit 8 is used twice each time in 288, 828, and 882. 

**Example 3:**

**Input:** digits = [3,7,5]

**Output:** []

**Explanation:** No **even** integers can be formed using the given digits. 

**Constraints:**

*   `3 <= digits.length <= 100`
*   `0 <= digits[i] <= 9`