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Java Solution for LeetCode algorithm problems, continually updating
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package g2301_2400.s2376_count_special_integers;
// #Hard #Dynamic_Programming #Math #2022_08_19_Time_0_ms_(100.00%)_Space_39.1_MB_(95.76%)
public class Solution {
private int[] cntMap;
// number n as an array, splitted by each digit
private int[] digits;
public int countSpecialNumbers(int n) {
if (n < 10) {
return n;
}
int len = (int) Math.log10(n) + 1;
cntMap = new int[len - 1];
int res = countUnbounded(len);
digits = new int[len];
for (int i = len - 1; i >= 0; i--, n /= 10) {
digits[i] = n % 10;
}
return res + dfs(0, 0);
}
private int dfs(int i, int mask) {
if (i == digits.length) {
return 1;
}
int res = 0;
for (int j = i == 0 ? 1 : 0; j < digits[i]; j++) {
if ((mask & (1 << j)) == 0) {
// unbounded lens left
int unbounded = digits.length - 2 - i;
res += unbounded >= 0 ? count(unbounded, 9 - i) : 1;
}
}
if ((mask & (1 << digits[i])) == 0) {
res += dfs(i + 1, mask | (1 << digits[i]));
}
return res;
}
private int count(int i, int max) {
if (i == 0) {
return max;
}
return (max - i) * count(i - 1, max);
}
private int countUnbounded(int len) {
int res = 9;
cntMap[0] = 9;
for (int i = 0; i < len - 2; i++) {
res += cntMap[i + 1] = cntMap[i] * (9 - i);
}
return res;
}
}