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Java Solution for LeetCode algorithm problems, continually updating
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2404\. Most Frequent Even Element
Easy
Given an integer array `nums`, return _the most frequent even element_.
If there is a tie, return the **smallest** one. If there is no such element, return `-1`.
**Example 1:**
**Input:** nums = [0,1,2,2,4,4,1]
**Output:** 2
**Explanation:**
The even elements are 0, 2, and 4. Of these, 2 and 4 appear the most.
We return the smallest one, which is 2.
**Example 2:**
**Input:** nums = [4,4,4,9,2,4]
**Output:** 4
**Explanation:** 4 is the even element appears the most.
**Example 3:**
**Input:** nums = [29,47,21,41,13,37,25,7]
**Output:** -1
**Explanation:** There is no even element.
**Constraints:**
* `1 <= nums.length <= 2000`
* 0 <= nums[i] <= 105