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g0001_0100.s0094_binary_tree_inorder_traversal.readme.md Maven / Gradle / Ivy

94\. Binary Tree Inorder Traversal

Easy

Given the `root` of a binary tree, return _the inorder traversal of its nodes' values_.

**Example 1:**

![](https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg)

**Input:** root = \[1,null,2,3\]

**Output:** \[1,3,2\] 

**Example 2:**

**Input:** root = \[\]

**Output:** \[\] 

**Example 3:**

**Input:** root = \[1\]

**Output:** \[1\] 

**Example 4:**

![](https://assets.leetcode.com/uploads/2020/09/15/inorder_5.jpg)

**Input:** root = \[1,2\]

**Output:** \[2,1\] 

**Example 5:**

![](https://assets.leetcode.com/uploads/2020/09/15/inorder_4.jpg)

**Input:** root = \[1,null,2\]

**Output:** \[1,2\] 

**Constraints:**

*   The number of nodes in the tree is in the range `[0, 100]`.
*   `-100 <= Node.val <= 100`

**Follow up:** Recursive solution is trivial, could you do it iteratively?