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Java Solution for LeetCode algorithm problems, continually updating
29\. Divide Two Integers
Medium
Given two integers `dividend` and `divisor`, divide two integers **without** using multiplication, division, and mod operator.
The integer division should truncate toward zero, which means losing its fractional part. For example, `8.345` would be truncated to `8`, and `-2.7335` would be truncated to `-2`.
Return _the **quotient** after dividing_ `dividend` _by_ `divisor`.
**Note:** Assume we are dealing with an environment that could only store integers within the **32-bit** signed integer range: [−231, 231 − 1]
. For this problem, if the quotient is **strictly greater than** [231 − 1]
, then return [231 − 1]
, and if the quotient is **strictly less than** [-231 − 1]
, then return [-231 − 1]
.
**Example 1:**
**Input:** dividend = 10, divisor = 3
**Output:** 3
**Explanation:** 10/3 = 3.33333.. which is truncated to 3.
**Example 2:**
**Input:** dividend = 7, divisor = -3
**Output:** -2
**Explanation:** 7/-3 = -2.33333.. which is truncated to -2.
**Example 3:**
**Input:** dividend = 0, divisor = 1
**Output:** 0
**Example 4:**
**Input:** dividend = 1, divisor = 1
**Output:** 1
**Constraints:**
* -231 <= dividend, divisor <= 231 - 1
* `divisor != 0`