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Java Solution for LeetCode algorithm problems, continually updating
86\. Partition List
Medium
Given the `head` of a linked list and a value `x`, partition it such that all nodes **less than** `x` come before nodes **greater than or equal** to `x`.
You should **preserve** the original relative order of the nodes in each of the two partitions.
**Example 1:**
![](https://assets.leetcode.com/uploads/2021/01/04/partition.jpg)
**Input:** head = [1,4,3,2,5,2], x = 3
**Output:** [1,2,2,4,3,5]
**Example 2:**
**Input:** head = [2,1], x = 2
**Output:** [1,2]
**Constraints:**
* The number of nodes in the list is in the range `[0, 200]`.
* `-100 <= Node.val <= 100`
* `-200 <= x <= 200`