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Java Solution for LeetCode algorithm problems, continually updating
package g0401_0500.s0472_concatenated_words;
// #Hard #Array #String #Dynamic_Programming #Depth_First_Search #Trie
// #2022_07_20_Time_84_ms_(74.09%)_Space_82_MB_(34.63%)
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
public class Solution {
private final List ans = new ArrayList<>();
private Trie root;
public List findAllConcatenatedWordsInADict(String[] words) {
root = new Trie();
Arrays.sort(words, (a, b) -> Integer.compare(a.length(), b.length()));
for (String word : words) {
Trie ptr = root;
if (search(word, 0, 0)) {
ans.add(word);
} else {
for (int j = 0; j < word.length(); j++) {
if (ptr.nxt[word.charAt(j) - 'a'] == null) {
ptr.nxt[word.charAt(j) - 'a'] = new Trie();
}
ptr = ptr.nxt[word.charAt(j) - 'a'];
}
ptr.endHere = true;
}
}
return ans;
}
private boolean search(String cur, int idx, int wordCnt) {
if (idx == cur.length()) {
return wordCnt >= 2;
}
Trie ptr = root;
for (int i = idx; i < cur.length(); i++) {
if (ptr.nxt[cur.charAt(i) - 'a'] == null) {
return false;
}
if (ptr.nxt[cur.charAt(i) - 'a'].endHere) {
boolean ret = search(cur, i + 1, wordCnt + 1);
if (ret) {
return true;
}
}
ptr = ptr.nxt[cur.charAt(i) - 'a'];
}
return ptr.endHere && wordCnt >= 2;
}
private static class Trie {
Trie[] nxt;
boolean endHere;
Trie() {
nxt = new Trie[26];
endHere = false;
}
}
}