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Java Solution for LeetCode algorithm problems, continually updating
1018\. Binary Prefix Divisible By 5
Easy
You are given a binary array `nums` (**0-indexed**).
We define xi
as the number whose binary representation is the subarray `nums[0..i]` (from most-significant-bit to least-significant-bit).
* For example, if `nums = [1,0,1]`, then x0 = 1
, x1 = 2
, and x2 = 5
.
Return _an array of booleans_ `answer` _where_ `answer[i]` _is_ `true` _if_ xi
_is divisible by_ `5`.
**Example 1:**
**Input:** nums = [0,1,1]
**Output:** [true,false,false]
**Explanation:** The input numbers in binary are 0, 01, 011; which are 0, 1, and 3 in base-10. Only the first number is divisible by 5, so answer[0] is true.
**Example 2:**
**Input:** nums = [1,1,1]
**Output:** [false,false,false]
**Constraints:**
* 1 <= nums.length <= 105
* `nums[i]` is either `0` or `1`.